Given that the equation m (x-1) = 2013-n (X-2) about X has infinitely many solutions, then what is the value of the 2013 times of M + the 2013 times of N? Urgent!!!!!!!!!!!!!!!!!!!!!!! Speed up!!!!!!!

Given that the equation m (x-1) = 2013-n (X-2) about X has infinitely many solutions, then what is the value of the 2013 times of M + the 2013 times of N? Urgent!!!!!!!!!!!!!!!!!!!!!!! Speed up!!!!!!!

Expansion m (x-1) = 2013-n (X-2) mx-m = 2013 NX + 2n
(m+n)x=2013+2n+m
There are infinitely many solutions,
So m + n = 0
2013+2n+m=0
So m = 2013, n = - 2013
So the original formula = 2013 & # 178; &# 186; &# 186; &# 179; - 2013 & # 178; &# 186; &# 186; &# 179; = 0

What is the solution of the equation 1 times 2 x plus 2 times 3 x plus. 2013 times 2014 x = 2013

(1 × 2) x + (2 × 3) x + +(2013 × 2014) x = 2013 [(1 × 2) 1 + (2 × 3) 1 +...] +(2013 × 2014) 1 / 2] x = 2013 (1-2 / 1 + 2 / 1-3 / 1 +...) +1 / 2013-1 / 2014) x = 2013 (1 / 2014) x = 20132014 / 2013x = 2013x = 2