M and N are prime numbers, and the square of 96 + n is equal to the square of m to find m and n

M and N are prime numbers, and the square of 96 + n is equal to the square of m to find m and n

m=11,n=5

If a and B are prime numbers, and a square minus 13A plus M = 0, b square minus 13b plus M = 0, then B of a plus a of B equals?

A^2-13A+M=0
B^2-13B+M=0
If a = b
B / A + A / b = 1 + 1 = 2
If a is not equal to B
Then AB is the solution of the equation x ^ 2-13x + M = 0
Then a + B = 13
13 is odd, so a and B are odd even
If the prime of even is 2, then the other is 13-2 = 11
So B / A + A / b = 11 / 2 + 2 / 11 = 125 / 22

The product of three prime numbers is exactly 11 times the sum of them. What are the three prime numbers?

Let these three prime numbers be a, B and C, then we can get the equation: ABC = 11 (a + B + C), and 11 is also prime, so one of a, B and C must be 11. Let a = 11, that is 11bc = 11 (11 + B + C) BC = 11 + B + C. when B and C contain prime number 2, we may as well make B = 22c = 11 + 2 + C, and solve C = 13, which is in line with the meaning of the problem When C is odd, let B = 2m + 1, C = 2n + 1, there are: (2m + 1) (2n + 1) = 11 + 2m + 1 + 2n + 1, that is, 4Mn = 12, Mn = 3 can only be m = 3, n = 1, then B = 2 × 3 + 1 = 7, B = 1 × 2 + 1 = 3, in line with the meaning of the problem

If the sum of squares of the two prime numbers is 125, then the sum of the two prime numbers is? If 1 / 8 = 1 / 9 + 1 / N, then n is? How many times between 3:00 and 4:00 is the angle between the hour hand and the minute hand 90 degrees?

If the sum of squares of two prime numbers is 125, then the sum of the two prime numbers is 13
n=72
Twice
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