A = log (3) π B = log (7) 6 C = log (2) 0.8 which is bigger,

π>3
Log3 (x) is an increasing function
So log3 (π) > log3 (3) = 1
a>1
one

Log (x) √ 8 = - 1 / 2 what is the value of this x~

log(x)√8=-1/2
log(x)√8=log(x)(1/√x)
√8=1/√x
The solution is x = 1 / 8

If log (2) 4 · log (4) 8 · log (8) M = log (4) 16, find the value of M

log(2)4·log(4)8·log(8)m=log(4)16
lg4/lg2*lg8/lg4*lgm/lg8=2
lgm/lg2=2
log(2)m=2
M = 2, square = 4

Let a = log (0.5) 6.7, B = log (2) 4.3, C = log (2) 5.6, how to compare the three numbers

Log0.5 (x) is a decreasing function
6.7>1
So log 0.5 (6.7) 1
So log2 (5.6) > log2 (4.3) > log2 (1) = 0
So c > b > 0
So c > b > a

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