Y = √ loga ^ (x-1)

Y = √ loga ^ (x-1)

∵ y = √loga^（x - 1）
(1) when a > 1, then
x - 1 ＞ 1
The solution is: x > 2
② When 0 < a < 1, then:
0 < x - 1

The domain of y = loga (loga ^ x)
May I have your advice

The definition field of y = loga (x) is x > 0, so this problem requires loga ^ x > 0
When a > 1, the domain is x > 1
When 0

Y = loga (1-x) ^ 2, find the definition field
Is x not equal to 1?

True number (1-x) ^ 2 > 0
therefore
X is not equal to 1
The domain is:
{x | x is not equal to 1}

Is the domain of y = loga x related to a
Is it 0 < a < 1, then 0 < x < 1, a > 1, then x > 1

It doesn't matter! A is the base, X is the index, the two are irrelevant