If a & # 178; > b > a > 1, compare log B B / A, log B a, log a B

If a & # 178; > b > a > 1, compare log B B / A, log B a, log a B

logb b/a-logb a=logb (b/a²)
∵a²>b>a>1
∴b/a²1
∴loga b>logb a
∴loga b>logb a>logb b/a

If 0
loga(b)

Because 0

It is known that log (14) 7 = A and log (14) 5 = B. try a and B to represent log (35) 28

log(14)7＋log(14)5＝㏒（14)35＝[㏒（35）35]／[㏒（35）14]＝1 ／ [㏒（35）14]＝a＋b；㏒（35）14＝1／（a＋b）log(14)7=[㏒（35）7]／[㏒（35）14]＝a ㏒（35）7＝a／（a＋b）㏒（35）14＝1／（a＋b）＝㏒（35）...

If the eccentricity of ellipse x ^ 2 / (log8 / loga) + y ^ 2 / 9 = 1 is known to be 0.5, then the value of a is obtained

If log (a) 8 > 9
The focus is on the X axis
c=√[log(a)8-9]
Then E = √ [log (a) 8-9] / √ log (a) 8 = 1 / 2
√log(a)8=2√[log(a)8-9]
log(a)8=4log(a)8-36
log(a)8=12
a^12=8
a=log(8)12
If log (a) 8