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If log3 (2) = A and 3 ^ B = 5, then a and B are used to denote that the root of log (3) is 30
b=log3(5)
Original formula = 1 / 2 * log3 (30)
=1/2*log3(2*3*5)
=1/2*[log3(2)+log3(3)+log3(5)]
=(a+b+1)/2
Log a Λ 8 = - 3, find the value of A
log a∧8=－3,
∴ a^(-3)=8
∴ 1/a³=8
∴ a³=1/8
∴ a=1/2
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