Given that the quadratic function y = ax ^ 2-4x + 13A has a minimum value of - 24, then a

Given that the quadratic function y = ax ^ 2-4x + 13A has a minimum value of - 24, then a

A = 2 divided by 13 or minus 2 (rounding)
-b/2a=2/a
-24 =... (bring x = 2 / A in)
Find a

If the minimum value of quadratic function y = ax * x + 4x + A-1 is 2, then the value of a is? A 4 B - 1 C 3 D 4 or - 1

Because it is the minimum value, then a > 0, one by one into the verification

When x = 3, the function has a minimum value of 5 and passes through points (1,11)

Let y = a (x-3) ^ 2 + 5, a > 0
Substituting the point (1,11), we get: 11 = a (1-3) ^ 2 + 5 > > A = 6 / 4 = 1.5
y=1.5(x-3)^2+5

If the quadratic function y = ax2-4x-13a has a minimum value of - 17, then a=______ ．

∵ the quadratic function y = ax2-4x-13a has a minimum value of - 17, ∵ a > 0, the minimum value of y = 4ac − b24a = (− 13) a × 4A − (− 4) 24a = - 13a2-4 = - 17, a = 1 or 413 is obtained