Using formula method to solve equation: (x)

Using formula method to solve equation: (x)

Using formula method to solve equation: (x + 2) &# 178; + 4x = 0
X ^ 2 + 4x + 4 + 4x = 0, that is, x ^ 2 + 8x + 4 = 0,
Formula of substituting root
The formula is: x = (- 8 ± √ (8 ^ 2-4 × 4)) / 2 = - 4 ± 2 √ 3

The solution equation is: x 2 + 3 = 3 (x + 1)

∵x2+3=3（x+1）∴x2+3=3x+3∴x2-3x=0∵x（x-3）=0∴x1=0，x2=3．

Using formula method to solve the equation: x ^ 2 - (√ 6 + √ 2) x + 2 √ 3 = 0 x ^ 2 - (2-2 √ 2) x + 3-2 √ 2 = 0

x^2-(√6+√2)x+2√3=0
(x-√6)(x-√2)=0
x1=√6,x2=√2
x^2-(2-2√2)x+3-2√2=0
(x-1)(x-2-2√2)=0
x1=1,x2=2-2√2

x^2-3mx+2m^2-mn-n^2=0
Help solve this equation
The value of X is finally expressed by an equation with Mn

Hehe, another slacker
Original formula = x ^ 2-3mx + (2m + n) (m-n)
Can you see that it can be divided into factors
1 -(2m+n)
1 -（m-n）
So, we can get (x-2m-n) * (x-m + n) = 0
Finally, X1 = 2m + N, X2 = m-n

The solution of the quadratic equation x2-3mx + 2m2-mn-n2 = 0 is______ ．

∵ b2-4ac = (− 3M) 2 − 4 × 1 × (2M2 − Mn − N2) = 9m2 − 8m2 + 4Mn + 4n2 = M2 + 4Mn + 4n2 = (M + 2n) 2 ∵ x = 3M ± & nbsp; (M + 2n) 22 = 3M ± (M + 2n) 2,