Given that the solutions of the equations x-m = x + m and X + 1 = 3x-2 are reciprocal, we can find the value of M

Given that the solutions of the equations x-m = x + m and X + 1 = 3x-2 are reciprocal, we can find the value of M

The solution of 3 / 3 x + 1 = 3x-2 is
x+1=9x-6 x=7/8
The solution of the reciprocal equation is x = 8 / 7
4/7=8/7+4m/3 4m/3=-4/7 m=-3/7

Let a, B, C be the three sides of △ ABC, and prove the necessary and sufficient condition that the equation x & # 178; + 2aX + B & # 178; = 0 and X & # 178; - 2cx-b & # 178; = 0 have common roots
Let a, B, C be the three sides of △ ABC, and prove that the equation x & # 178; + 2aX + B & # 178; = 0 and X & # 178; - 2cx-b & # 178; = 0 have common roots if and only if the angle a is equal to 90 degrees

Sufficiency because a is equal to 90 degree, B2 + C2 = A2 is substituted into X & # 178; + 2aX + B & # 178; = 0 and X & # 178; - 2cx-b & # 178; = 0 to get X & # 178; + 2aX + a2 - C2 = 0 (x + a) 2 = C2 to get X & # 178; - 2cx-b & # 178; = 0 to get X & # 178; - 2cx - A2 + C2 = 0 to get (x-C) 2 = A2 to get common root

Let a, B and C be trilateral of △ ABC, and two equations: X & # 178; + 2aX + B & # 178; = 0 and X & # 178; + 2cx-b & # 178; have a common root,
Determine the shape of △ ABC

Let m be the public root of M, then m \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\b: B: B: B: B: B: B: B: B: B: B: B: B: B: B: B: B: B: B: B

We know that a, B and C are three sides of △ ABC. If the equation x ^ 2 + 2aX + B ^ 2 = 0 about X has equal roots, we prove that a = B

Because the equation x ^ 2 + 2aX + B ^ 2 = 0 about X has equal roots;
So: (2a) ^ 2-4 * (b ^ 2) = 0;
That is, a ^ 2-B ^ 2 = 0;
So (a + b) (a-b) = 0;
So a = - B or a = B
And because a > 0 and b > 0 (a, B are the sides of triangle), so a = B

a. B and C are the three sides of △ ABC, if the equation 2aX & # 178; + 2 / sqrt {B & # 178; + C & # 178;} x + (B + C) = a has two equal real roots
If the equation 2aX & # 178; + 2 / sqrt {B & # 178; + C & # 178;} x + (B + C) = a has two equal real roots, judge the shape of △ ABC

△=b²-4ac=0
4(b²＋c²)-8a（b+c-a)=0
b²＋c²-2ab-2ac+2a²=0
a²-2ab＋b²＋a²-2ac+c²=0
(a-b)²＋(a-c)²=0
a-b=0 a-c=0
a=b=c
ABC is an equilateral triangle

If A.B.C is three sides of triangle ABC and a × CoSb = B × cosa, there are two equations B (X & sup2; - 1) - C (X & sup2; + 1) - 2aX = 0 about X
If A.B.C is the three sides of triangle ABC, and a × CoSb = B × cosa, the equation B (X & sup2; - 1) - C (X & sup2; + 1) - 2aX = 0 about X has two equal real roots, find the degree of A.

b(x^2-1)- c（x^2+1）-2ax=0
bx^2-b- cx^2-c-2ax=0
(b-c)x^2-2ax-b-c=0
△=4a^2-4(b-c)(-b-c)
=4a^2+4(b-c)(b+c)
=4a^2+4b^2-4c^2
4a^2+4b^2-4c^2=0
c^2=a^2+b^2
So the triangle ABC is a right triangle
a*cosB= b*cosA
asinA= bcosA
sinA/cosA=b/a
tanA=b/a
tanA=a/b
b/a=a/b
a^2= b^2
So the triangle ABC is an isosceles right triangle
That is, a = 45 degrees

How to calculate the formula of (x + y) 3

(x+y)3=x³＋3x²y＋3xy²＋y³

If x = 25, the values of X and y are
A. 26 and 25 b.25 and 26 c.25 and 25 d.26 and 26
Please write down the ideas and steps to solve the problem

Y = x + + is actually equivalent to executing two statements, the first is y = x; X = x + 1; in this way, the value of Y is 25 and the value of X is 26
But if the original sentence is y = + + X, this is different
This sentence is equivalent to the following two sentences: x = x + 1; y = x;
So both X and y are 26
This is the difference between I + + and + + I!

If x = 5, y = 10, then calculate the value of X and y after y * = + + X expression

x=6,y=60
Because + + has higher priority than * =, execute + + first, x = 6, and then y * = 6 = 60

If * is a new algorithm, let a * b = AB + B of a, then - 2 * (x + 2) = 5, x =?

-2*(x+2)=5
-2 × (x + 2) + (x + 2) = 5
Multiply both sides by - 2
4(x+2)+(x+2)=-10
5x+10=-10
5x=-20
x= -4