4400 M = () cm

4400 M = () cm

four hundred and forty thousand

Solve the equation, {(x + 2) &# 178; - (y + 4) &# 178; = (x + y) (X-Y), x-3y = - 2, using the square difference

The x-3-y-2 (x + 2 + 2 + y + 4) (x + 2 + 2 + y + 4) (x + 2-y-2-y-4) is the x-3y-2 (x + 2 + 2 + 2 + y + 4) X-2 (x + 2 + 2 + y + 2 + 4) X-2 (x + 2 + y + 2 + 4) X-2 (x + 2 + 2 + y + 4 + 4) (x-2-y-2-y-4) is the x-\\#\35;\\\\\\\\\\\\\\\\\\\\\\\\- Y & # 178; - 4x-8y = 0, x = 3y-2-4

How to solve the equation 4x + 10 = [x + 10] times 2-2?

4x+10=2(x+10)-2
4x+10=2x+20-2
4x+10=2x+18
4x-2x=8
2x=8
x=4

The solution equation: 1.2 / y + 3Y / Y-1 = 32. X + 1 / x-1-4 / X & # 178; - 1 = 13.2 / X-1 = 4 / X & # 178; - 1

1.2/y + 3Y / Y-1 = 3 multiply both sides of the equation by Y (Y-1) to get 2y-2 + 3Y & # 178; = 3Y & # 178; - 3y5y = 2 # y = 2 / 5 test: y = 2 / 5 is the solution of the equation; 2.x + 1 / x-1-4 / X & # 178; - 1 = 1 multiply both sides by (x + 1) (x-1) to get X & # 178; + 2x + 1-4 = x & # 178; - 12x = 2x = 1 test: x = 1 is the increasing root; 3.2 / X-1 = 4 / X & # 178; - 1 two

X ^ 2-4x = 5x + 10, x = 10 and x = - 1, that's the solution of the equation

x^2-4x=5x+10
x^2-9x-10=0
(x-10)(x+1)=0
X = 10 or x = - 1
They are all solutions of the equation

To solve the equation two-thirds X & # 178; = five seventh x requires two answers, the same as (3y-4) &# 178; - (Y-1) &# 178; = 0

Two thirds X & # 178; = five seventh x multiplied by 2114x & # 178; = 15x14x & # 178; - 15x = 0x (14x-15) = 0x = 0 or x = 15 / 14 (3y-4) & # 178; - (Y-1) & # 178; = 0 (3y-4 + Y-1) (3y-4-y + 1) = 0 (4y-5) (2y-3) = 0y = 5 / 4 or y = 3 / 2, we are very happy to answer for you

Is x = - 1 the solution of the equation x ^ 2-4x = 5x + 10

X = - 1 is the solution of the equation x ^ 2-4x = 5x + 10
Substituting x = - 1, both sides are equal to 5

The square of 3T + 2t-1 = 0

The square of 3T + 2t-1 = 0
The square of 3T + 2t-1
=(t+1)*(3t-1)
So the square of 3T + 2t-1 = 0
That is, (T + 1) * (3t-1) = 0
T = - 1, or T = 1 / 3

() is the solution of the equation 4x △ 5 = 10

x=12.5
Is the solution of the equation 4x △ 5 = 10

How to solve the square of 2t-3t-2 = 0?

2t²－3t－2=0
(2t＋1)(t－2)=0
2T + 1 = 0 or T-2 = 0
The results are as follows
T = - 1 / 2 or T = 2