If the distance between a point m on hyperbola x24-y212 = 1 and its right focus is 3, then the abscissa of point m is___ ．

If the distance between a point m on hyperbola x24-y212 = 1 and its right focus is 3, then the abscissa of point m is___ ．

Let the abscissa of the point m be m. from the standard equation of hyperbola, we can get a = 2, B = 23, C = 4, A2C = 1. Then from the definition of hyperbola, we can get & nbsp; & nbsp; 3m-a2c = e, 〈 3m-1 = 2, M = 52, so the answer is & nbsp; 52

A focus of hyperbola x-square-k / y-square = 1 is (2.0), then the value of real number k is

The focus of X & # 178; - Y & # 178 / k = 1 is (2,0)
So a & # 178; + B & # 178; = C & # 178;
1+k=2²
k=4-1=3
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Given that a focus of the hyperbola KX ^ 2-2ky ^ 2 + 1 = 0 is (- 4,0), then the real number k is
-3/32
It's all - root 5 / 8
What's wrong? I'm so angry

Hyperbola KX ^ 2-2ky ^ 2 + 1 = 0,
Then K ≠ 0, 2ky ^ 2-kx ^ 2 = 1
If a focus is (- 4,0), then the focus is on the X axis, so K

A focus of hyperbola 5x2 + ky2 = 5 is (6,0), then the value of real number k is ()
A. -25B. 25C. -1D. 1

Because the hyperbolic equation 5x2 + ky2 = 5, so a = 1, B2 = - 5K, so C2 = 1-5k, because a focal coordinate (6, 0) of the hyperbola, so 1-5k = 5, so k = - 1