(1) find the value of 5 * (- 5) (2) solve the equation, 2 * (2 * χ) = 1 * χ

(1) find the value of 5 * (- 5) (2) solve the equation, 2 * (2 * χ) = 1 * χ

5*（－5）=5/3-(-5)/4=5/3+5/4=35/12
2*（2*χ）=1*χ
2*(2/3-x/4)=1/3-x/4
2/3-(2/3-x/4)/4=1/3-x/4
2/3-1/6+x/16=1/3-x/4
1/2+x/16=1/3-x/4
5x/16=-1/6
x=-8/15

The new operation "*" is defined in the range of rational number, and its rule is a * b = A / 2-B, and the solution of equation 2 * (x * 1) = 1 is obtained

2 ★ (x / 2-1) = 1
2 / 2-1 (x / 2-1) = 1
X/2=|
X=2

For rational numbers a and B, the meaning of operation * is defined as: a * b = 2a-3b, then the solution of equation 4 * (3-x) = 5 is

a*b=2a-3b,4*(3-x)=2*4-3*(3-x)=5 8-9+3x=5 x=2

Given that I a i + a = 0, then √ (A-1) ^ 2 + √ a ^ 2 is equal to______ (√ denotes arithmetic square root)

|A | + a = 0, so | a | = - A, a