Given a two digit number, its ten digit number is 1 larger than the one digit number. If you exchange the number on the one digit number with the number on the ten digit number, the new number is 9 smaller than the original number. Find the number To process (2 yuan 1 time) detailed point thank s We all know that

Given a two digit number, its ten digit number is 1 larger than the one digit number. If you exchange the number on the one digit number with the number on the ten digit number, the new number is 9 smaller than the original number. Find the number To process (2 yuan 1 time) detailed point thank s We all know that

twenty-one
Let ten bits be x and one bit be y
x-y=1
10x+y=10y+x+9
x-y=1
x=2,y=1
twenty-one
x=3,y=2
thirty-two
x=4,y=3
forty-three
x=5,y=4
fifty-four
.
65,76,87,98.
A total of 8

How do you calculate that nine numbers from 1 to 9 are subtracted by three digits, and different three digits are equal to the other three digits
The number cannot be repeated

927 -346=581
972-358=614
819-452=367

A ten is a three digit zero, which is exactly 67 times the sum of the numbers
A ten digit is a three digit number of 0, which is exactly 67 times of the sum of its numbers. After exchanging its one digit number and hundred digit number, a new three digit number is obtained, which is exactly m times of the sum of its numbers
(using the binary linear equation solution of the second volume of the seventh grade)

Let the hundreds be x and the ones be y
Then: 100x + y = 67 (x + y)
X = 2Y
100y+x=m（x+y）
So: M = 34

For a two digit number, the sum of one digit number and ten digit number is equal to 9. If you add 27 to the two digit number, it is just equal to the two digit number and ten digit number

Let the number's single digit be x, then the ten digit is 9-x. according to the meaning of the question: 10 × (9-x) + X + 27 = 10x + (9-x), the solution is x = 6, so the ten digit of the number is 9-x = 3, and the number is 36