A ten digit is a three digit number of 0, which is exactly equal to 67 times of the sum of its numbers; after swapping its three digit numbers in the hundreds, we get a new three digit number, which is exactly the same Is the m times of the sum of the numbers that make it up. Find the value of M
Let X be a hundred digit number and y be a single digit number,
Then 100x + y = 67 (x + y), 100y + x = m (x + y)
The sum of the two formulas leads to
101(x+y)=(67+m)(x+y)
Obviously, x + y ≠ 0
So 101 = 67 + M
m=34
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