The coordinates and focal length of the focus of the hyperbola x2-y2 = 4

The coordinates and focal length of the focus of the hyperbola x2-y2 = 4

(- 2,0) (2,0). Focal length 4

A mathematical problem: hyperbola x2-y2 / 8 = 1, F1F2 are two focuses, P is on hyperbola, and Pf1: PF2 = 3:4, find the area of triangle pf1f2

Using the second definition of hyperbola, the abscissa of the point is 7 / 3, and the area is 8 √ 5

If the focus of the parabola y2 = 2px coincides with the right focus of the hyperbola x2 / 6 + Y2 / 2, then the value of P is zero

It should be x ^ 2 / 6 + y ^ 2 / 2 = 1. So the right focus is (2,0); the parabolic focus is (P / 2,0). P = 4