Given that the length of the major axis of the focus F1 (- 2, radical 2,0) and F2 (2, radical 2,0) of the ellipse C is 6, the standard equation of the ellipse C is solved. Let the line y = x + 2 intersect the ellipse C at two points a and B, and the coordinates of the midpoint of the line AB are obtained

Given that the length of the major axis of the focus F1 (- 2, radical 2,0) and F2 (2, radical 2,0) of the ellipse C is 6, the standard equation of the ellipse C is solved. Let the line y = x + 2 intersect the ellipse C at two points a and B, and the coordinates of the midpoint of the line AB are obtained

Given that the two focal points of hyperbola are the two vertices of ellipse x2100 + y264 = 1, and the two quasars of hyperbola pass through the two focal points of ellipse, then the equation of hyperbola is ()
A. x260−y230＝1B. x250−y240＝1C. x260−y240＝1D. x250−y230＝1

The focus of hyperbola is on x-axis and C = 10, A2C = 6 {A2 = 60, B2 = c2-a2 = 40, so the equation of hyperbola is x260 − y240 = 1

The asymptote equation of hyperbola with the focus of ellipse x28 + Y25 = 1 is ()
A. y=±35xB. y=±53xC. y=±155xD. y=±153x

According to the meaning of the title, the focus coordinate of the ellipse x28 + Y25 = 1 is (± 3,0), the vertex coordinate of the hyperbola is (± 3,0), the vertex of the ellipse is the focus of the hyperbola, the focus of the hyperbola is (± 8,0), in the hyperbola, B2 = c2-a2 = 5, and the asymptote equation of the hyperbola is y = ± 153x

An elliptic equation is as follows. What is the chord length passing through its focus and perpendicular to the major axis of the ellipse?
(x²/a²)+(y²/b²)=1
And a > b > 0

If we know (X & sup2 / A & sup2;) + (Y & sup2 / B & sup2;) = 1 and a > b > 0, then the ellipse focal coordinates are (C, 0) and the abscissa of the intersection point (that is, c) in the elliptic equation, and the focal coordinates of the chord and ellipse are (C, - B & sup2 / a) and (C, B & sup2 / a), so the chord length is 2B & sup2 / A