Calculation of X & # 178; - 1 / X & # 178; - 2x + 1 + X & # 178; - 2x / X-2 △ x process

Calculation of X & # 178; - 1 / X & # 178; - 2x + 1 + X & # 178; - 2x / X-2 △ x process

The original formula = (x + 1) (x-1) / (x-1) &# 178; - x (X-2) / (X-2) △ x
=(x+1)/(x-1)-1
=(x+1-x+1)/(x-1)
=2/(x-1)

Calculation: X & # 178; - 2x / X & # 178; - 4 △ 2x / x + 2 + (x + 2); (1 / A + 2-1) △ A & # 178; - 1 / A + 2

x²-2x/x²-4÷2x/x+2+(x+2);
=[x(x-2)/(x-2)(x+2)]÷2x/(x+2)+(x+2)
=[ x/x+2](x+2)/2x+(x+2)
=1/2+x+2
=x+3/2
(1/a+2-1)÷a²-1/a+2
=(1-a-2)/(a+2)÷a²-1/a+2
=(-1-a) /(a+2)÷ (a+1)(a-1)/(a+2)
=-1/( a-1)
=1/(1-a)

(2x-3) &# 178; = (X-2) &# 178;

(2x-3) & #178; = (X-2) & #178; (2x-3) & #178; - (X-2) & #178; = 0; [(2x-3) + (X-2)] [(2x-3) - (X-2)] = 0; (3x-5) (x-1) = 0; 3x-5 = 0 or X-1 = 0; X = 5 / 3 or x = 1; I'm glad to answer for you, skyhunter 002 will answer your questions for you. If you don't understand this question, you can follow up