Is a right triangle a RT triangle if it is not a triangle proved by HL? Is there something unnecessary that can be omitted

Is a right triangle a RT triangle if it is not a triangle proved by HL? Is there something unnecessary that can be omitted

There are several situations that you don't need to thank RT:
1. This triangle is not proved by HL;
2. Before proving the triangle, it is written that one angle of the triangle is 90 degrees;
3. This triangle has no condition for HL to hold in proving congruence
However, in general, or to add to the best

Can the method of proving the congruence of triangles be applied to proving the congruence of right triangles?

Yes
Because right triangles are also a kind of triangles

If two triangles are right triangles, how can we prove that they are congruent?

HL
SSS
SAS
ASA

As shown in the figure, the right triangle ABC (angle a = 30) with 30 angles is rotated a degree (0-90) around its vertex C along with the needle to obtain RT triangle a'b'c, where a'c and ab intersect with point D
Make de parallel to a'B 'through point D, intersect c'd' at point E, and connect be. It is known that in the process of rotation, the triangle BDE is a right triangle. Let be = 1, ad = x, and the area of triangle BDE is s
1. When a = 30 °, find the value of X
2. Find the functional relationship between S and X, and write the value range of X
3. Make circle e with point E as the center and be as the radius. When s = 1 / 4S triangle ABC, judge the position relationship between circle E and a'c, and find the value of Tana

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