Suppose there is an inscribed triangle PAB in the ellipse 3x2 + y2 = 6, the inclination angle of the straight line passing through O and P is 60 degrees, and the slope of the straight line AP and BP meets the condition K AP + K BP = 0 Verification: the slope of the straight line passing through a and B is a fixed value

Suppose there is an inscribed triangle PAB in the ellipse 3x2 + y2 = 6, the inclination angle of the straight line passing through O and P is 60 degrees, and the slope of the straight line AP and BP meets the condition K AP + K BP = 0 Verification: the slope of the straight line passing through a and B is a fixed value

First, it is easy to find P (1, √ 3 (root sign 3)). Let the straight line AP be y - √ 3 = K (x-1), and then eliminate it with the elliptic equation to get (k * 2 + 3) x * 2 + + (2 √ 3k-2k * 2) x + k * 2-2 √ 3k-3 = 0. Let a (x1, Y1), B (X2, Y2). According to Weida's theorem, XP × X1 = k * 2-2 √ 3k-3 / k * 2 + 3, and XP = 1  X1 = k * 2-2 √ 3-3 / 3

The square of 6x minus 5x is equal to 2

If 6x & # 178; - 5x = 2, then 6x & # 178; - 5x-2 = 0
Where a = 6, B = - 5, C = - 2
Then △ = B & # 178; - 4ac = 25 + 48 = 73
So the solution of the equation is x = (5 ± root 73) / 12

What is the square of 2x times the square of X?

How about 2x times the square of X () 2x? "()" filled with greater than, less than or equal to
Urgent!

2X times the square of X (=) 2x