Equation: the square of 4x - 8x + 1 = 0 is solved by formula method | Math enthusiast | Mathematical art

Equation: the square of 4x - 8x + 1 = 0 is solved by formula method

x²-2x+1/4=0
x²-2x+1-1+1/4=0
(x-1)²-3/4=0
(x-1+√3/2)(x-1-√3/2)=0
The solution is x = 1 - √ 3 / 2 or x = 1 + √ 3 / 2

The formula method is used to solve the following equation: the square of 0.4x-0.8x = 1

That is X & # 178; - 2x = 2.5
x²-2x+1=2.5+1
(x-1)²=7/2
x-1=±√14/2
x=(2-√14)/2,x=(2+√14)/2

The square of 4x + 8x + 1 = 0 is solved by formula method

4X ^ 2 – 8x + 1 = 0, get: 4x ^ 2-8x = - 1, first term coefficient into 1, get: x ^ 2-2x = - 1 / 4 formula [add the absolute value of half product of first term coefficient and second term coefficient on both sides], get: x ^ 2-2x + 1 = - 1 / 4 + 1 factorization, get (x-1) ^ 2 = 3 / 4 [both sides square at the same time], get X-1 = ± √ 3 / √ 4, X-1 = ± √ 3 / 2, so X1 = √ 3 / 2 + 1, X2 = - √ 3 / 2 + 1
Hope to solve your problem

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