There is a section of conductor. When the voltage at both ends is 2 V, the current passing through it is 0.5 A, and the resistance of this section of conductor is () A. if the applied voltage is zero, the current passing through it is () a, and the resistance of this section of conductor is () Ω

There is a section of conductor. When the voltage at both ends is 2 V, the current passing through it is 0.5 A, and the resistance of this section of conductor is () A. if the applied voltage is zero, the current passing through it is () a, and the resistance of this section of conductor is () Ω


R = u / I = 2 / 0.5 = 4 ohm
There is no voltage, so there is no current, so I = 0A. Resistance is a basic property of an object. Whether there is voltage or not, it exists objectively, so the resistance does not change, r = 4 ohm



When a voltage of 2V is applied at both ends of a conductor and the current passing through is 0.5A, the resistance of this section of conductor is?
In order to make the current passing through the conductor become 1a, the current should be added at both ends of the conductor_______ When the voltage at both ends of the conductor is 10V, the electric power consumed by the conductor is_______ W.


When 2V voltage is applied at both ends of a conductor and the current passing through is 0.5A, the resistance of this section of conductor is 4
In order to make the current passing through the conductor become 1a, the current should be added at both ends of the conductor___ 4__ V voltage
When the voltage at both ends of the conductor is 10V, the electric power consumed by the conductor is___ 25___ W.
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The difference between short circuit and open circuit short circuit. Does open circuit have voltage and current?
There isn't much time. The day after tomorrow, there will be an exam


Open circuit literally means that the circuit has been cut off. Where is the current coming from? But if a voltmeter is used to connect the two ends of the disconnected circuit, there is also voltage
Short circuit is that there is no resistance in the circuit, the positive and negative poles of the power supply are directly connected together, I = E / R, r = 0, so the power supply will burn out