The resistance of an electric lamp is 10 ohm. The normal operation is that the voltage at both ends of the lamp should be 5 V, but the current power supply around us is 8 v How much resistance does it need to connect in series to make the lamp work normally?

The resistance of an electric lamp is 10 ohm. The normal operation is that the voltage at both ends of the lamp should be 5 V, but the current power supply around us is 8 v How much resistance does it need to connect in series to make the lamp work normally?


In the circuit, the current I = u lamp / R lamp = 5V / 10 Ω = 0.5A
Resistor sharing voltage ur = U-U lamp = 8v-5v = 3V
Resistance value of series resistance R = ur / I = 3V / 0.5A = 6 Ω



When the voltage at both ends of a fixed value resistor is 4 V, the current passing through it is 0.5 A. if the voltage at both ends of the resistor increases to 5 V, can the current with the range of 0.6 a be used
Ammeter to measure the current through the resistance


No, because the resistance value r = u / I = 4 / 0.5 = 8 ohm, the current I = u / r = 5 / 8 = 0.625 at 5V has exceeded



There is a small light bulb. When it works normally, the resistance is 10 Ω and the voltage is 4V. There is only a 6V power supply and several 10 Ω resistors on hand. How can it work normally?


The normal working voltage of the small bulb is 4V, while the power supply voltage is 6V. Therefore, the method of series voltage division can be used to make the small bulb work normally. According to the principle of series voltage division, 4 / 10 = (6-4) / R, r = 5ohm, so the 5ohm resistance can be obtained by paralleling two 10ohm resistors, and then it can be connected in series with the small bulb



When an electric bell works normally, its resistance is 10 ohm, and its voltage is 4V, but there is only a 6V power supply and several 10 ohm resistors on hand
How to make the bell work normally? Try to answer by calculation


First of all, the current of the bell is 4V / 10 Ω = 0.4A
With 6V voltage on hand, the total resistance of the circuit is 6V / 0.4A = 15 Ω
If two 10 Ω resistors are connected in parallel, the resistance of the parallel circuit is 5 Ω
If it is connected in series with the bell, the total resistance is 15 Ω