As shown in the figure, the power supply voltage remains unchanged, the range of ammeter is 0 ~ 3a, and the resistance R2 = 10 Ω

As shown in the figure, the power supply voltage remains unchanged, the range of ammeter is 0 ~ 3a, and the resistance R2 = 10 Ω


(1) When the switch S is off, the reading of the ammeter is 1.2A, calculate the power supply voltage; (2) when the switch S is closed, calculate the current indication of the ammeter when the slide P of the sliding rheostat is at the right end; (3) when the switch S is closed, calculate the minimum resistance of the sliding rheostat



As shown in the figure, the power supply voltage is 9V, the amperemeter indication is 0.3A, and the resistance R2 = 10 Ω. Calculate the resistance value of the resistance R1


1. Calculate the voltage of R2 resistor: U2 = IR = 0.3 * 10 = 3V
2. Calculate the voltage of R1 resistor: U1 = u-u2 = 9-3 = 6V
3. The current of series circuit is equal everywhere, and the resistance of R1: R1 = U1 / I = 6 / 0.3 = 20 Ω



The power supply voltage remains unchanged, the range of ammeter A is 0-3A, and the resistance value of resistor R2 is 12 Ω. Close the switch and move the sliding rheostat to the midpoint of ammeter 2A;
Move the rheostat to the maximum value. The ammeter is 1.5A. Calculate the maximum resistance and power supply voltage. R2 is connected in parallel with the rheostat. The total current is measured by the ammeter


Because R2 is in parallel with the rheostat, the total resistance of the two is 0.5r · 12 / (0.5r + 12) for the first time and R · 12 / (R + 12) for the second time



As shown in the figure, in the circuit, the power supply voltage U = 4.5V remains unchanged, the resistance R1 = 5 Ω, the maximum resistance of rheostat R2 is 20 Ω, the range of ammeter is 0 ~ 0.6A, the range of voltmeter is 0 ~ 3V, which is to protect the ammeter, and the resistance range of rheostat access circuit is ()
A. 2.5~10ΩB. 0~20ΩC. 2.5~20ΩD. 0~10Ω


It can be seen from the circuit diagram that R1 and R2 are connected in series, the voltmeter measures the voltage at both ends of R1, and the ammeter measures the current in the circuit. (1) when the resistance of the sliding rheostat in the circuit increases, the total resistance in the circuit increases, ∵ I = ur, ∵ the indication of the ammeter in the circuit decreases, and the indication of the voltmeter in parallel at both ends of R1 decreases, then the resistance of the sliding rheostat can be fully connected into the circuit, that is (2) when the indication of the voltmeter is 3V, the current in the circuit is I = u1r1 = 3v5 Ω = 0.6A, ∵ the range of the ammeter is 0 ~ 0.6A, ∵ the current in the circuit is I '= 0.6A, the resistance of the sliding rheostat in the circuit is the minimum, and the total resistance in the circuit is r = UI' = 4.5v0.6a = 7.5 Ω, ∵ the total resistance in the series circuit is equal to the sum of the partial resistances, ∵ the sliding rheostat in the circuit To sum up, the resistance range of sliding rheostat access circuit is 2.5 Ω ~ 20 Ω, so select C