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The experimental equipment includes an ammeter with a range of (0 ~ 0.6A, 0 ~ 3a), a voltmeter with a range of (0 ~ 3V, 0 ~ 15V), a sliding rheostat (1a, 18 Ω) and a power supply (6V). If the resistance of about 6 Ω is measured with the above equipment, then: (1) in order to form the experimental circuit, in addition to the above equipment, it is necessary to______ One, at least______ (2) the range of current variation in the circuit is about______ (3) it is required that the pointer of ammeter and voltmeter should not exceed the range in the experiment, and the pointer of ammeter and voltmeter should be deviated from the middle line of the dial when measuring data for several times______ Range, voltmeter should be used______ Range
(1) In the experiment of measuring resistance by voltammetry, in addition to the equipment listed in the title, a switch is also needed to control the on-off of the circuit; five wires are needed to connect the power supply, switch, sliding rheostat, resistance to be measured and ammeter in series, and two wires are needed to connect the voltmeter to both ends of the resistance to be measured in parallel, so at least seven wires are needed to connect the experimental circuit When the resistance value of sliding rheostat is zero, the circuit current is the largest, I max = ur = 6v6 Ω = 1A; when the resistance value of sliding rheostat is all connected to the circuit, the circuit current is the smallest, I min = ur + R sliding = 6v6 Ω + 18 Ω = 0.25A; the current variation range in the circuit is about 0.25 ~ 1A; therefore, the answer is: 0.25 ~ 1a. (3) the power supply voltage is 6V < 7.5V, use the 0 ~ 15V range of the voltmeter, the voltmeter The pointer can't deviate over the middle line of the dial, so the voltmeter can't use the range of 0 ~ 15V, only the range of 0 ~ 3V; when using the range of 0 ~ 3V of the voltmeter, the maximum voltage at both ends of the resistance to be measured is 3V, and the maximum current of the circuit is I = UVR = 3v6 Ω = 0.5A ＜ 1.5A. When using the range of 0 ~ 3a of the ammeter, the pointer of the ammeter can't deviate over the middle line of the dial of the ammeter, so the ammeter can't use the range of 0 ~ 3a The range of ammeter should be 0 ~ 0.6A, so the answer is: 0 ~ 0.6A; 0 ~ 3V
Can we use "0-0.6a, 0-3A" dual range ammeter, "0-3v" voltmeter, "0-25 Ω" sliding resistance transformer
Can we use "0-0.6a, 0-3A" dual range ammeter, "0-3v" voltmeter, "0-25 Ω" sliding rheostat, a number of wires, a switch, a power supply composed of three dry batteries (the voltage does not change during use) and other equipment to measure the rated power of a small bulb marked with "3.0V, 0.5A"? Explain the reason
Circuit structure: connect the bulb, ammeter (with 0.6A range), sliding rheostat and switch in series to both ends of the power supply, and then connect the voltmeter (with 3V range) to both ends of the bulb
The laboratory has an ammeter (0 ~ 0.6A 3a), a voltmeter (0 ~ 3V 15V), a sliding rheostat (0 ~ 10 Ω) and a power supply 6V
The laboratory has the following equipment: an ammeter (0 ~ 0.6A 3a), a voltmeter (0 ~ 3V 15V), a sliding rheostat (0 ~ 10 Ω), a power supply 6V, and several wires. If the above equipment is used to measure the resistance of about 6 Ω:
(1) It is required that the ammeter should choose the range of (0-0.6a) under the condition that the pointer of the ammeter neither exceeds the range nor deviates from the middle line of the dial
The answer is that when the resistance of the sliding rheostat is 0, the maximum current is 0.5A
Why? Isn't the maximum current 1A?
COME ON BABY
I'm not very good at physics either. I'm not sure I'm right. I just give you a suggestion. 1a is definitely wrong, and 1A doesn't pass the middle line of the dial of the ammeter. Because if the current is 1a, the measuring range of 0 ~ 3a is needed. The middle line is 1.5A, and 1A doesn't pass the middle line. Because the pointer is required to pass the line of the dial, the circuit must be in series (if
In the circuit shown in the figure, the power supply voltage remains unchanged, and the resistance value of resistance R1 is 20 Ω
In the circuit as shown in the figure, the power supply voltage remains unchanged, and the resistance value of resistance R1 is 20 Ω. Close switch s, the indication value of ammeter A1 is 0.3A, and that of ammeter A2 is 0.2A. Calculate: (1) power supply voltage U; (2) resistance value of resistance R2
S close R1 R2 in parallel, the voltage at both ends of R1 R2 is equal and equal to the power supply voltage
(1) If R1 = 20 Ω, I1 = 0.3A, U1 = I1 * R1 = 0.3A * 20 Ω = 6V, that is, u = 6V
（2）U2=U1=6V
R2=U2/I2=6V/0.2A=30Ω
RELATED INFORMATIONS
- 1. In the experiment of exploring the relationship between current and voltage, resistance, when exploring the relationship between current and resistance, we should () A. Adjust the sliding rheostat to keep the current in the circuit constant B. Adjust the sliding rheostat so that the voltage at both ends of different fixed resistor R remains unchanged C. Make the voltage at both ends of resistance R change in multiple D. The current in the circuit should be changed in multiple during each measurement
- 2. The resistor R1 and R2 are connected in series on the power supply with a voltage of 4.5V. The resistance of R1 is known to be 5 Ω, and the voltage at both ends of R2 is 3V. The total resistance in the circuit and the total resistance through R2 are calculated The resistance of an electric bell is 10 Ω. When it works normally, the voltage at both ends is 4V. Now it is connected to 9V power supply. In order to make it work normally, how much resistance should it be connected in series?
- 3. The resistance R1 and R2 are connected in series in the circuit, the voltage at both ends of R1 is 3V, R2 voltage is 9V, R1 + R2 = 600 Ω
- 4. If the voltage applied to both ends of a fixed value resistor increases from 6V to 10V and the current through the resistor changes by 0.1A, the electric power of the resistor changes () A. 1.6WB. 4.0WC. 0.4WD. 3.4W
- 5. There is a small bulb marked with "3V 1.5W" and resistor R1 in series in the circuit with 9V power supply. If the small bulb works normally for 1 minute, it is related to R1 in series? Chasing points There is a small bulb marked with "3V 1.5W" and resistor R1 in series in the circuit with 9V power supply. How to calculate the physical quantity related to R1 in series when the small bulb works normally for one minute?
- 6. In the series circuit, the rated voltage of a small bulb is 2.4V, and the resistance is 8 when the lamp is normally emitting. If there is only 3V power supply, if the bulb is normally emitting What is the resistance in series? (common series circuit)
- 7. There is a small light bulb. The resistance of the filament is 5 Ω when it lights normally, and the voltage required for normal operation is 2.5V. If we only have a 6V power supply, we need to make the small light bulb work normally______ The first resistance is______ The resistance in Ω
- 8. If the filament of a light bulb has been used for a long time, will the resistance of the filament increase or decrease? Why?
- 9. The rated voltage of a bulb is 2.5V. Now, how to connect it to a 6V power supply Rated power is 5W) small light bulb can normally light up
- 10. A 10 ohm resistor, a 3V voltage source, a 3A current source. Series. Power A 10 ohm resistor, a 3V voltage source and a 3A current source. In series, what is the power of the current source? (the current direction of the current source is the negative pole of the voltage source)
- 11. In the circuit as shown in the figure, the specifications of the two ammeters are the same. The ammeter has two ranges (0-0.6a and 0-3A). When the switch S is closed, the current flows through the resistance R1 and R2. If the pointer deflection angle of the two ammeters is the same, the ratio of R1 to R2 is () A. 1：5B. 5：1C. 1：4D. 4：1
- 12. As shown in the figure, the power supply voltage remains unchanged, the range of ammeter is 0 ~ 3a, and the resistance R2 = 10 Ω
- 13. The title is "the circuit diagram of the experiment of measuring resistance by volt ampere method". In the diagram, there are ammeter (range 0 ~ 0.6A, 3a), voltmeter (range 0 ~ 3V, 15V), sliding rheostat (range of resistance value 0 ~ 12ohm), resistance Rx to be measured (about 6ohm, calculated as 6ohm) and power supply composed of three new dry batteries in series, I don't understand why the maximum current in the circuit is 0.75a, but the solution judges that the range of 0-0.6a should be selected. When the ammeter selects the range of 0-0.6, the maximum voltage at both ends of the constant resistance is 3.6V, but the solution judges that the range of 0-3v should be selected, Isn't that against the norm?
- 14. What is the resistance of 3A 0.6A ammeter? What about a 3V, 15V voltmeter?
- 15. The current is 1a and the voltage is 5V. How many resistances do you need to reduce the voltage to 4, 3, 2 and 1V
- 16. DC power supply 5V need resistance to step down to 4V, limit current in 4.5a need a few w several r resistance?
- 17. When the voltage at both ends of the resistor increases from 2V to 4V, the current intensity through the resistor changes by 0.25A, Then the resistance of the constant resistance ro is____ Ohm. The electrical power of the resistance ro increases____ w. This is to fill in the blanks!
- 18. Whether a small light bulb emits light depends on what? Rated voltage, rated current or resistance, or rated power
- 19. When exploring the relationship between the current and voltage on the resistance, the sliding rheostat changes the voltage at both ends of the light bulb, while the book says that the voltage of the small light bulb is larger, There's a lot of current in the circuit, but I feel it doesn't matter
- 20. How to find the resistance of light bulb?