If the voltage at both ends of a section of conductor is 12 V and the current in the conductor is 2 A, the resistance of the conductor itself is 0___ If the voltage drops to 6 V, the current in the conductor is___ When the voltage drops to 0 V, the resistance of the conductor is equal to____ .

If the voltage at both ends of a section of conductor is 12 V and the current in the conductor is 2 A, the resistance of the conductor itself is 0___ If the voltage drops to 6 V, the current in the conductor is___ When the voltage drops to 0 V, the resistance of the conductor is equal to____ .

Answer: first empty: according to the deformation formula of Ohm's law, r = u / I = 12V / 2A = 6ohm
The second space: I = u / r = 6V / 6eu = 1a,
Third space: as resistance is an attribute of conductor itself, it has nothing to do with current passing through, so it is still 6 Ω

When the voltage at both ends of a resistor increases from 2.5 V to 3.5 V, the current through the resistor increases by 1 A. what is the resistance value of the resistor

Set the resistance to R
According to the meaning of the title:
3.5/R-2.5/R=1
We can know by solving the equation
R = 1 ohm

When the voltage at both ends of an appliance increases from 2 V to 2.8 V, the current through the resistor increases by 0.1 A. what is the resistance value of the resistor?

(2.8－2)÷0.1=8

470 ohm resistor connected to 12 V, how much is the current?

I=U/R=12/470=0.0255 A