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Resistor R1 and R2 are connected in parallel in the circuit. The voltage applied at both ends is 24 v. if R1 is 80 Ω, the current through R2 is 0.2 a, and R2 is calculated?
Because the voltage at both ends of the two resistors in parallel is equal, they are both 24 v,
Method 1: R2 = 24 / 0.2 = 120 ohm
Method 2: the R1 current is 24 / 80 = 0.3A
3 + 0.2 = 0.5
The total resistance is 24 / 0.5 = 48 ohm
R1R2/(R1+R2)=48
It can be found that R1 = 120
Resistor R1 and R2 are connected in parallel in the circuit, and the voltage applied at both ends is 24 v. if R2 is 80 Ω, the current through R1 is 0.2 a, there are two methods to calculate R2
The first is parallel connection. The voltage of R2 is 24 V, R2 = 24 / 0.2 = 120 Ω
The second and the first method is the simplest and most direct one
If the calculation method, what grade are you in? Set X to calculate, the results are all the same. The second method makes friends very boring
Connect 5 Ω resistor R1 and 18 Ω resistor R2 in series with an ammeter to the power supply. The degree of the ammeter is 0.3A. What is the voltage of the power supply
There are two ways
(5+18)X0.3=6.9V
The resistance values of R1 = 3 ohm and R2 = 6 ohm are connected in parallel with the power supply. The current in the main circuit is 1.5A measured by an ammeter,
Ask the voltage at both ends of each resistor. And the current through each resistor. Urgent!
Total circuit resistance = (r1r2) / (R1 + R2) = (3x6) / (3 + 6) = 2 Ω
Voltage = RI = 2 × 1.5 = 3V
Through R1 current = u / R1 = 3 △ 3 = 1A
Through R2 current = u / r2 = 3 △ 6 = 0.2A
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