A light bulb is printed with "PZ & nbsp; 220 & nbsp; & nbsp; 40". How much resistance does it have when it works normally? If it is connected to a 110V circuit, what is the actual power consumption?

A light bulb is printed with "PZ & nbsp; 220 & nbsp; & nbsp; 40". How much resistance does it have when it works normally? If it is connected to a 110V circuit, what is the actual power consumption?


Its normal working resistance R = u2p = (220V) 240W = 1210 Ω, put it into a 110V circuit, its actual consumption of electric power is p real = U2 real r = (110V) 21210 Ω = 10W. Answer: its normal working resistance is 1210 Ω, put it into a 110V circuit, its actual consumption of electric power is 10W



The resistance of an electric iron is 0.1 kiloohm, and the current is 2.1a when it is used. What is the voltage applied to the electric iron?
10 points


Electric iron is a pure resistance of electrical appliances, Ohm's law can be applied
0.1k ohm = 100 ohm
Voltage U = current I * resistance R = 2.1 * 100 = 210v
So the voltage applied to the iron is 210 volts



The resistance of an electric iron is 0.1k Ω, the current flowing through is 2.1a, what is the voltage applied to the electric iron?


The voltage applied to the electric iron: u = IR = 2.1a × 100 Ω = 210v. A: the voltage applied to the electric iron is 210v



The resistance of an electric iron is 0.1k Ω, the current flowing through is 2.1a, what is the voltage applied to the electric iron?


The voltage applied to the electric iron: u = IR = 2.1a × 100 Ω = 210v. A: the voltage applied to the electric iron is 210v