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If there is a 20 ohm resistor and the power consumed within 30 minutes is 1 kW. H, what is the current through the resistor
Q = the square of I * r * t, 1000 = the square of I * 20 * 0.5 hours, the others are calculated by yourself. (the premise is that in the pure resistance circuit, all electric energy is converted into heat energy, which is applicable.) ask: the answer is A20 B18 C36 D10, which is it
When a constant resistance with a resistance value of 4 Ω passes through a current of 0.5 A, the heat generated in 1 min is 0______ J．
The heat generated in t = 1mim = 60s: q = i2rt = (0.5A) 2 × 4 Ω × 60s = 60j; so the answer is: 60
The resistance is 4 ohm, the current passing through is 2a, and the heat generated in 1 min is 1
The resistance is 4 ohm, the current passing through is 2a, and the heat generated in 1 min is 1
Q=I²Rt
=2²×4×60
=960J
The resistance of a conductor is 2 Ω. How many joules of heat are generated in one minute when the current is 2A?
T = 1min = 60s, q = i2rt = (2a) 2 × 2 Ω × 60s = 480j A: the heat generated in 1min is 480j
RELATED INFORMATIONS
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