Resistor R1 = 4 Ω, R2 = 6 Ω, connected in series in the circuit, the ratio of voltage at both ends of them is (:), the ratio of current passing through them is (:), The ratio of current to work in the same time is (:). In the circuit connected in parallel, the ratio of voltage at both ends is (:), the ratio of current passing through them is (:), and the ratio of current to work in the same time is (:)

Resistor R1 = 4 Ω, R2 = 6 Ω, connected in series in the circuit, the ratio of voltage at both ends of them is (:), the ratio of current passing through them is (:), The ratio of current to work in the same time is (:). In the circuit connected in parallel, the ratio of voltage at both ends is (:), the ratio of current passing through them is (:), and the ratio of current to work in the same time is (:)

（2：3） （1：1） （2：3） （1：1） （3：2） （3：2）
The previous empty is R1

R1 and R2 are connected in parallel on the circuit, the voltage is 24 V, resistance 1 is 80 Ω, resistance 2 is 0.2 a, calculate resistance 2
In two ways

Method 1: regardless of resistance 1, resistance 2 = u / I = 24 V / 0.2A = 120 Ω
Method 2: I1 = u / R1 = 24 V / 80 Ω = 0.3A
Because R1 and R2 are in parallel, the current distribution is inversely proportional to the resistance
So R2 / R1 = I1 / I2
R2=R1(I1/I2)=80Ω(0.3A/0.2A)=80Ω×1.5=120Ω