Two resistors R1 and R2 are connected in parallel in the circuit. If the current I1: I2 passing through the resistor R1 and R2 is 4:3, the voltage ratio at both ends of the resistor R1 and R2 is () A.4:9 B:1:1 C.3:2 D.2:3

Two resistors R1 and R2 are connected in parallel in the circuit. If the current I1: I2 passing through the resistor R1 and R2 is 4:3, the voltage ratio at both ends of the resistor R1 and R2 is () A.4:9 B:1:1 C.3:2 D.2:3


B;
In parallel, the voltage at both ends is equal, and the series current is equal;
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R1 = 3 ohm, R2 = 4 ohm two resistors are connected in parallel in the circuit. After being electrified, what is the heat ratio Q1 / Q2 at the same time? What is the current ratio I1 / I2


Parallel circuit, branch voltage equal
So Q1: Q2 = P1: P2 = u ^ 2 / R1: u ^ 2 / r2 = R2: R1 = 4:3
I1:I2=U/R1:U/R2=R2:R1=4:3



As shown in the figure, R1 = 5 ohm, R2 = 20 ohm. It is known that the current I1 passing through R1 is 0.4A. Calculate the voltage at both ends of the circuit and the current passing through resistance R2
As shown in the figure, the resistance value of resistance R1 is 5 ohm, the current in the trunk circuit is 0.5A, and the voltage at both ends of resistance R2 is 2V. Calculate (1) the current passing through R1 (2) the current passing through R2 (3) the resistance value of R2


(1) Because the two resistors are in parallel:
U1=U2=2V
According to Ohm's Law:
I1=U1R1=2V5Ω=0.4A;
(2) According to the current law of parallel circuit, it can be seen that:
I2=I-I1=0.5A-0.4A=0.1A;
(3) The voltage and current of R2 are 2V and 0.1A respectively;
Then the resistance of R2:
R2=U2I2=2V0.1A=20Ω;
A: (1) the current through R1 is 0.4A; (2) the current through R2 is 0.1A; (3) the resistance of R2 is 20 Ω



The unknown resistance R and 20 ohm resistance R1 are connected in series to the power supply, and the measured current through R1 is I1 = 0.4A. Then R and 50 ohm R2 are connected in series to the same power supply


Regardless of R, R2 increases by 2.5 times from 20 to 50, because r remains unchanged, u remains unchanged, so the total resistance increases by 2.5 times, the current decreases by 2.5 times, 0.4 / 2.5 = 0.16A. OK, 100% is like a fake replacement!