The panel of household electric energy meter is marked with 3600 rpm, which is connected to a 220 V 40 W electric appliance. When it works normally, the power of the electric energy meter will be reduced within one minute

The panel of household electric energy meter is marked with 3600 rpm, which is connected to a 220 V 40 W electric appliance. When it works normally, the power of the electric energy meter will be reduced within one minute

No matter how many revolutions it takes, it's kilowatts per hour. That's 40 watts per hour now. If you want to find how many revolutions it takes, 3600 / 1000 = 36, that's 36 revolutions per watt. The revolutions of a 40 Watt electric appliance in an hour are 36 * 40 = 1440, 60 minutes per hour, 1440 / 60 = 24, that's 24 revolutions per minute····

Turn off all electrical appliances. Let a 220 V, 1210 w work. Observe the watt hour meter to rotate for 3 minutes and 180 turns. Set the resistance unchanged
Find the actual electrical rate when the resistance of electric kettle works. The actual voltage of the student's home

R=U∧2/P=220∧2/1210=40Ω
3600r / kW · h means to turn 3600 turns and walk 1kW · H
So 180 turns is 180 / 3600 = 1 / 20kw · H
3 minutes = 3 / 60 hours = 1 / 20 hours
Then the actual electric power P = w / T = (1 / 20) / (1 / 20) = 1kW = 1000W
Actual voltage U = √ PR = √ (1000 * 40) = 200V
The resistance of electric kettle is 40 Ω, the actual electric power is 1000W and the actual voltage is 200V

The electric energy meter in a family circuit is marked with "220V & nbsp; 10A" and "3000r / kW · H". Question: (1) what is the maximum power that the family can use electrical appliances at the same time? (2) If only an electric appliance is allowed to work, and the turntable of the electric energy meter rotates for 60R within 5min, what is the electric power of the electric appliance?

(1) The maximum power of the household can use electrical appliances at the same time: P = UI = 220 V × 10 a = 2 200 W; (2) the electric energy consumed by the rotary table of the electric energy meter for 60 R is: w = 603 000 kW · H = 0.02 kW · h, and the electric power of the electrical appliances is: P = wt = 0.02 kW · H560 H = 0.24 kW = 240 W. answer: (1) the maximum power of the household can use electrical appliances at the same time is 2 200 W; (2) the electric power of the electrical appliances is 240 W

The electric energy meter is marked with the word "3000r / kW · H". If only one electric appliance works in the circuit where the meter is located, and the turntable of the electric energy meter turns 30 turns in 6 minutes, how much electric energy is consumed by the electric appliance? What is the current through it?

It can be seen from the meaning of the question that the work done by the appliance w = 303000kw · H = 3.6 × 104j, according to the formula w = uit, I = wut = 36000j220v × 360s = 0.45a