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Take any number of natural numbers, of which the difference between two numbers must be a multiple of 3
Take 4 scallops
Because the remainder of a natural number divided by 3 is nothing more than 0, 1, 2
There are three kinds of remainder
It's like three drawers. Only when you put four numbers in a drawer can you ensure that there are two numbers in it. And the difference between the two numbers can be divided by three
At 1, 2, 3 Of the 2000 natural numbers, there are______ Natural numbers can be divisible by 2 and 3 at the same time, and cannot be divisible by 5
The number that can be divisible by 2 and 3 at the same time, that is, the number that can be divisible by 6 is 1, 2, 3 There are 6, 12, 18, 24 Let there be n such numbers, then: 1998 = 6 + (n-1) × 6, n = 333. Therefore, there are 333 numbers divisible by 2 and 3 at the same time. Among these 333 numbers, 30, 60, 90, 120 Suppose there are m such numbers, then 1980 = 30 + (m-1) × 30, M = 66, that is, there are 66 numbers divisible by 5. Therefore, there are 333-66 numbers divisible by 2 and 3 at the same time, and there are 267 numbers divisible by 5
At 1, 2, 3 How many of 2000 natural numbers can be divided by 2 and 3 at the same time, and can't be divided by 5
I don't have a reward. Please help me
There are 333 common multiples of 6 that can be divisible by 2 and 3 at the same time, and there are 66 common multiples of 30 that can be divisible by 2, 3 and 5 at the same time, so 333-66 = 267
Super simple)___ Divide any natural number and any non-zero natural number___ .
0 divides any natural number, and any non-zero natural number divides 1
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