There are four natural numbers, each of which can not be divided by the other three numbers, but the product of any two of them can be divided by the other two numbers. The sum of these four numbers is the least equal to______ ．

According to the meaning of the question, the form of the four numbers should be: AB, AC, ad, BC, where a, B, C, D are coprime, and can not be 1. Take the smallest three, the number of two coprime 2, 3, 5, 7, get the four numbers respectively: 2 × 3 × 5 = 302 × 3 × 7 = 422 × 5 × 7 = 703 × 5 × 7 = 10530 + 42 + 70 + 105 = 247. Answer: the minimum value of the sum of the four natural numbers is 247

Each of the three natural numbers cannot be divided by the other two. The product of any two numbers can be divided by the third number. What is the minimum sum of these three numbers
Do me a favor and train my mind

Let a, B and C be prime numbers, then AB, AC and BC can satisfy the condition that the three numbers should be minimum

If a ／ B ／ = 3 (AB is a natural number greater than 1), then () is a factor of () and () is a multiple of (), () can be divisible by (), () can be divisible by (), and () has () factors of A
There is another way:
Uncle Li has a deposit of 5 digits, which is a multiple of 2.3.5. The first two digits are 2, and the last two digits are 25. This deposit is () yuan

If a △ B = 3 (AB is a natural number greater than 1), then (b) is the factor of (a), and (a) is a multiple of (b), (a) can be divided by (b), (b) can be divided by (a), and there are (4) factors of A
The second question is wrong and cannot be answered

The minimum natural number which is not only a multiple of 2, but also a multiple of 3 and 5 is (). There are () factors in this number

2 × 3 × 5 = 30
The minimum natural number is (30), which has (8) factors

There are four natural numbers, each of which can not be divided by the other three numbers, but the product of any two of them can be divided by the other two numbers. The sum of these four numbers is the least equal to______ ．