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Xiaoming and Xiaoqiang walk to school. Xiaoming walks one fifth more than Xiaoqiang. Xiaoqiang spends one eleventh less time than Xiaoming. Find the speed ratio between Xiaoming and Xiaoqiang Xiaoming and Xiaoqiang walk to school. Xiaoming walks one fifth more than Xiaoqiang. Xiaoqiang spends one eleventh less time than Xiaoming. What's the speed ratio between Xiaoming and Xiaoqiang
Hello, lovely dumplings
Time ratio: 1: (1-1 / 11) = 11:10
Distance ratio: (1 + 1 / 5): 1 = 6:5
Speed ratio: (6 / 11): (5 / 10) = 12:11
1. The number of people in the class is fixed. Is the number of people in each group inversely proportional to the number of people in each group? Why? 2. Is the walking speed and time from home to school of Xiao Ming proportional
1. Because the number of each group × the number of groups = the total number of the class (a certain number), the number of each group shrinks, the number of each group expands, the number of each group expands, the number of groups shrinks, and the number of the whole class remains unchanged
2. Xiao Ming's distance from home to school is certain. Speed × time = distance (certain), so it is in inverse proportion
When Xiao Ming walks from home to school, what's the ratio between the speed of walking and the time needed, and why
S = VT, when s is fixed, that is, the distance is fixed, the faster the speed, the shorter the time
From the school to the children's palace, Xiaoming walked for 20 minutes and Xiaoqiang walked for 16 minutes. What percentage of Xiaoming's speed is Xiaoqiang's?
1/20÷1/16=80%
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- 1. Xiaoming walks from place a to place B, and Xiaoqiang walks from place B to place a at the same time. When they reach the destination, both sides immediately return. During the walking process, their respective speeds remain unchanged. The first time they meet is 40 kilometers away from place a, and the second time they meet is 15 kilometers away from place B. then the distance between a and B is______ Kilometers
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