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The speed ratio of a and B is 3 to 2. They start from a and B at the same time. After 10 minutes, they meet on the way. How many minutes does it take for a to get to B?
3 + 2 is 5, time is 5, 3 / 5 times 10 is 6 minutes, then divide 6 by corresponding score, 3 / 5 is 10 minutes, then answer a to B to take 10 minutes
When they set out, their speed ratio was 3:2. After their first meeting, a's speed increased by 20%, and B's speed increased by 30%. In this way, when a arrives at B, B is still 14 kilometers away from a, so how many kilometers is the distance between a and B?
Suppose the distance between a and B is SKM, and the speed of a and B is 3x and 2x respectively. When a and B meet for the first time, the distance they take is 3s5 = 0.6skm and 2s5 = 0.4skm respectively. According to the time series equation of a to B after meeting: 0.4s3x (1 + 20%) = 0.6s − 142x (1 + 30%), s = 45km. A: the distance between a and B is 45km
When they set out, the speed ratio of a and B was 3:2. After their first meeting, the speed of a remained the same,
%When a arrives at B, B is 28 kilometers away from a
Let AB be s, the velocity of a be 3V, and it takes t for a and B to start and meet
3VT+2VT=S
S/(3V)=T+[(3/5)S-28]/(2.4V)
Simulink regards VT as an unknown number and gets s = 100
A and B are going towards each other. The distance between a and B is 150km. A's speed is 10km / h. After 40 minutes, they meet
Let B speed be XKM / h,
150=(40/60)10+(40/60)X
150=6.6+0.6X
143.4=0.6X
X=239km/h.
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