Car a and car B start from city a and car C start from city B. car a runs 40 kilometers per hour and car B runs 50 kilometers per hour. If three cars are facing each other at the same time However, car C can't meet car a until 10 minutes after meeting car B. please find the distance between a and B cities C is an unknown condition

One condition is missing, such as car C a km / h
Let AB distance s km, S / (a + 40) - S / (a + 50) = 1 / 6, s = (A & # 178; + 90a + 2000) / 60 km
S = 120 (km) when a = 40. S = 150 (km) when a = 50

A and B start from city a, C start from city B, a car runs 40 kilometers per hour, B car runs 50 kilometers per hour, if three cars at the same time

Let C meet B after X hours. So, 40 (x + 1 / 6) + 50 (x + 1 / 6) = 45x + 50x, then x = 3 hours. So AB distance = 45x + 50x = 45 * 3 + 50 * 3 = 285 (km)

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