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Car a and car B drive from two places 360 kilometers apart. Car a travels 64 kilometers per hour. Car B's speed is 78 times that of car A. how many hours do the two cars meet?
360 (64 + 64 × 78), = 360 (64 + 56), = 360 (120), = 3 (hours), a: after 3 hours, the two cars meet
Two cars a and B leave 1080km away from each other at the same time. They meet eight hours later. The speed of car B is two-thirds of that of car a, and that of car a is two-thirds of that of car a
Speed sum = 1080 △ 8 = 135 km / h
Speed of car a = 135 (1 + 2 / 5) = 81 km / h
Car a and car B leave from both places at the same time. Car a travels 80 kilometers per hour, and car B travels 7 / 8 of the speed. After 3 hours, the two cars are still far away from each other
10%. How many meters is the distance between the two places?
Speed of car B: 80 × 7 / 8 = 70 km / h
In three hours, the two trains were running: (80 + 70) × 3 = 450 km
Distance between the two places: 450 ÷ (1-10%) = 500 km
After four hours of meeting, we know that the speed ratio of the express train to the local train is 5:4, and how much does the local train travel per hour
Kilometers?
Set the speed of fast train 5x and that of slow train 4x
（5x+4x）*4=360
36x=360
x=10
Slow train 4x = 40 km per hour
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