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The distance between a and B is 800 kilometers. AB and ab cars are facing each other from the two places. It is known that the speed ratio of AB car is 3:5. How many kilometers did the two cars travel when they met Two solutions
A car 800 × 3 / (3 + 5)
=800×3/8
=300 km
B car 800 × 5 / (3 + 5)
=800×5/8
=500 km
The speed of the freight car is 95% of that of the passenger car. The two cars drive from two places at the same time and meet at 8 kilometers away from the destination. Find the distance between the two places~
It's from the end!
Error, must be midpoint:
8÷【1/2-95%/（95%+1）】
=8÷【1/2-19/39】
=8÷1/78
=624 km
The two passenger and freight cars drive from two places at the same time. They meet in 9 hours. When they meet, the passenger car takes 3 / 5 of the whole journey, and the freight car is 15 kilometers slower than the passenger car per hour
Within 9 hours, the passenger car runs 9 × 15 kilometers more than the freight car. At the same time, the passenger car runs 3 / 5 of the whole journey, and the freight car runs 1-3 / 5 = 2 / 5 of the whole journey, so 9 × 15 is 3 / 5 - (1-3 / 5) = 1 / 5 of the whole journey, so the distance between the two places is 9 × 15 △ 1 / 5 = 9 × 15 × 5 = 675 kilometers
Formula:
9 × 15 / (3 / 5 - (1-3 / 5)) = 9 × 15 × 5 = 675 (km)
When the passenger car exceeds 56 km from the midpoint, the freight car is 38 km away from the midpoint. It is known that the speed ratio of the passenger car and the freight car is 3:2
The distance of ab
Let the distance of AB be s, then:
（S/2+56）：（S/2-38）=3：2
The solution is s = 452
So the distance of AB is 452km
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