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A and B start from a to B at the same time. The speed of a is 3 / 5 of that of B. when B arrives at the ground, he returns immediately and meets a on the way A and B start from a to B at the same time. The speed of a is 3 / 5 of B's speed. When B returns to the ground immediately, he meets a on the way. He only knows that it takes 60 minutes for a and B to go back and forth between AB and how long does it take each
Speed ratio: A: B = 3:5
Time ratio: A: B = 5:3
The time required for the distance of one AB between a and B: 60 △ 2 = 30 (minutes)
One round trip of car a between ab: 30 + 30 △ 3x5, X2 = 160 (minutes)
One round trip of car B between AB and ab requires: [30 + 30 △ 5x3] x2 = 96 (minutes)
On a main highway, there are two places (A and b) 480 km apart. The fast and slow trains run from the two places at the same time and meet each other in 6 hours. The speed of the fast train is 11 / 9 of that of the slow train
480 △ 6 = 80 km / h
Slow speed 80 ÷ (1 + 11 / 9) = 36 km / h
Express speed 80-36 = 44 km / h
On a main highway, there are two places, a and B, 480 kilometers apart. The fast and slow cars run from the two places at the same time and meet at 6 o'clock,
9 out of 11,
Sum of speed of two vehicles = 480 △ 6 = 80 (km)
Express speed = 80 ÷ (1 + 9 / 11) = 44 (km)
Idle speed = 80-44 = 36 (km)
There are 480 kilometers of a and B on a main highway. The two fast and slow cars travel from the two places at the same time. They meet in six hours. What is the speed ratio of the two fast and slow cars
11: 9. What's the speed of the two cars?
Speed sum = 480 △ 6 = 80 km
80÷（11+9）=4
Express speed = 4x11 = 44km
Slow speed = 4x9 = 36km
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