Two cars a and B depart from ab at the same time. Two hours later, they meet at a distance of 15 kilometers from the destination. It is known that the speed of car a is 7 / 10 of that of car B, so the distance of AB can be calculated

B took the whole journey of 1 / 17 (1 + 7 / 10) = 10 / 17
Distance: 15 ÷ (10 / 17-1 / 2) = 15 ÷ 3 / 34 = 170 km

A and B leave from ab at the same time, and a meets B at the end of 12 kilometers. It is known that the speed ratio of a and B is 5:3. How many kilometers are there between a and B

A meets B 12 km from the end
My estimate is: a meets B at 12 kilometers past the midpoint
(12 + 12) / ((5-3) / 5 + 3) = 96 km

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