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The distance between city a and city B is 600km. The two cars start from the two cities at the same time and drive for 5 hours. It is known that the speed ratio of car a and car B is 5:7 The distance between city a and city B is 600km. The two cars start from the two cities at the same time and drive for 5 hours. It is known that the speed ratio of car a and car B is 5:7. What is the speed of the two cars
Speed sum of two vehicles per hour: 600 △ 5 = 120 km
Speed of car a: 120 △ 12x5 = 50km
Speed of car B: 120 △ 12x7 = 70km
If the distance between Party A and Party B is 600km, they will meet after 6 hours. If Party B meets after 3 hours, Party A meets after 5 hours,
How much do you get by writing the formula without unit
B: go first and meet after 3 hours
The speed sum of a and B is: 600 / 6 = 100
So the distance of B in 3 hours is 600-100 * 5 = 100 km
B's speed is 100 / 3
A's speed is 100-100 / 3 = 200 / 3
The distance between a and B is 600 kilometers. Car a and B start from two places at the same time and meet each other in 5 hours. It is known that the speed of car a is three fourths of that of car B, so the speed of car B can be calculated
The distance between a and B is 600 kilometers. Car a and B start from two places at the same time and meet each other in 5 hours. It is known that the speed of car a is three fourths of that of car B,
Let the speed of car B be 4x
7x x 5 = 600
x = 120 / 7
4x = 480 / 7
The speed of car B is 480 / 7 km / h
/It's a fraction line
Car a and car B leave 324km apart at the same time. After six hours, they meet on the way. The speed of car a is% of that of car B
Two cars a and B leave 324km apart at the same time. After six hours, they meet on the way. The speed of car a is 80% of that of car B. what's the speed of car a?
The speed sum of a and B is: 324 / 6 = 54 km / h
B's speed is 54 / (1 + 0.8) = 30 km / h
Then the speed of a is: 30 * 80% = 24 km / h
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