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A passenger car travels 50 kilometers per hour and a freight car 55 kilometers per hour. The two cars leave each other at the same time. When they meet, the freight car travels 7.5 meters more than the passenger car How many kilometers are there between the two places
(50+55)*(7.5÷（55-50）)=105*（7.5÷5）=105*1.5=157.5
Distance = time required for speed and * to meet
The distance between a and B is 345 kilometers. The bus and the freight car run from each other at the same time. Three hours later, the two cars meet on the way. It is known that the bus runs 65 kilometers per hour on average, and the freight car runs how many kilometers per hour. 2. In a book, the number of pages read is two times more than the number of pages not read. How many pages have been read? How many have not been read? Both problems need to be solved by equations
1.345/3-65 = 50 km / h
3x+3*65=345
x=50
2. A book has 75 pages, and the number of pages read is one-half more than the number of pages not read. How many pages have you read? How many pages have you not read?
Let x pages be viewed and 75-x pages not be viewed
x=(75-x)*(1+1/2)
x=45
75-45=30
I've read 45 pages, but there are still 30 left
The distance between a and B is 345 km. A car and a freight car leave the two places at the same time. They meet in three hours. The bus runs 55 km per hour and the freight car runs 55 km per hour
equation
The truck runs every hour
=345÷3-55
=105-55
=50 km
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The distance between a and B is 345km. A bus and a freight car leave from the two places at the same time and meet in three hours. The bus runs 55km per hour, and the freight car runs thousands per hour
Truck speed = 345 △ 3-55 = 60 km / h
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