It takes 8 hours for the express train from a to B, and 10 hours for the slow train. When they meet, they travel 40 km faster than they do. Find the distance between a and B

It takes 8 hours for the express train from a to B, and 10 hours for the slow train. When they meet, they travel 40 km faster than they do. Find the distance between a and B


It takes 8 hours for the express train and 10 hours for the local train, indicating that the speed of the express train is 5:4 higher than that of the local train
When the two cars meet, the time is equal, and the speed is 40km more than the full distance. This shows that 40km accounts for 5-4 = 1 share, and the total is 9 shares. Therefore, the distance is 9 × 40 = 360km



The express train runs 80 kilometers per hour from place a to place B, and the local train runs 65 kilometers per hour from place B to place a at the same time. The speed sum of the two trains is () kilometers per hour
If the two cars meet in six hours, the distance between a and B is () km


Speed sum: 80 + 65 = 145 (km)
Distance between the two places: 145 * 6 = 870 (km)



Let me ask you, it takes 8 hours for the express train from a to B, and 10 hours for the local train. How much faster is the express train than the local train, and how much slower is the local train?


(1/8-1/10)÷1/10=25%
(1/8-1/10)÷1/8=20%
Please click "select as satisfactory answer"



From place a to place B, the fast train takes 8 hours and the slow train takes 10 hours. What is the speed ratio between the slow train and the fast train?


Slow speed: fast speed = 1 / 10:1 / 8 = 4:5