An express train and a local train leave from a and B at the same time. They run in opposite directions. They met on the way when they were 4 hours old. The speed ratio of the express train and the local train is 3:2, which is the same The fast train runs 140 kilometers more than the slow train in case of time, so as to find the distance between a and B

An express train and a local train leave from a and B at the same time. They run in opposite directions. They met on the way when they were 4 hours old. The speed ratio of the express train and the local train is 3:2, which is the same The fast train runs 140 kilometers more than the slow train in case of time, so as to find the distance between a and B

Let the fast train speed be 3x and the slow train speed be 2x 3x * 4 - 2x * 4 = 140 x = 35
The speed of the express train is 105 and that of the local train is 70
Distance between two places: (105 + 70) * 4 = 700

An express train and a local train leave at the same time from two stations 576km apart, and meet four hours later. It is known that the speed of the express train is twice that of the local train. How many kilometers do the two trains travel per hour?

(1) Slow train speed: 576 △ 4 △ 2 + 1, = 144 △ 3, = 48 (km). (2) fast train speed: 48 × 2 = 96 (km). Answer: fast train runs 96 km per hour, slow train 48 km per hour

The two trains are going from place a to place B at the same time. The express trains travel 18 km more per hour than the express trains. The express trains return after 4 hours and meet the local trains at 42 km away from place B. the distance between the express trains and the local trains is very long
The two trains go from place a to place B at the same time. The express trains travel 18 km more per hour than the express trains. The express trains return 4 hours later and meet the local trains 42 km away from place B. what is the distance between a and B?

Suppose the speed of the express is x, then the distance between a and B is 4x, and the speed of the local train is x-18. It takes 42 / X for the express to start from B to meet the local train, so it takes 4 + 42 / X for the local train to start from a and turn with the express, and the distance is 4x-42, so (4 + 42 / x) * (x-18) = 4x

Two cars start from a to B at the same time. The express train travels 6 kilometers per hour more than the local train. The faster one passes B 30 minutes earlier than the local train. When the local train reaches C, the express train travels 30 kilometers to B to find the distance between a and C

When the local train arrives at C, the fast train and the slow train run for 30 △ 6 = 5 hours
30 minutes = 0.5 hours
The express speed is 30 △ 0.5 = 60 km / h
The idle speed is 60-6 = 54 km / h
The distance between the two places is 54 × 5 = 270 km
Or 60 × 5-30 = 270 km