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A rides a motorcycle while B rides a bicycle. At the same time, a and B are 250 kilometers apart. After five hours of meeting, it is known that the distance a travels per hour is six kilometers less than three times that B travels per hour. How to find the speed of B's bicycle [solve the problem with the equation of one variable once]
A rides a motorcycle and B rides a bicycle from two places 150 kilometers apart. After five hours of meeting, it is known that the distance a travels per hour is the distance b travels per hour
The distance per hour is three times that of B, less than 6 kilometers
solve equations:
1】2x+3【2x-1】=16-【x+1】
2】 2 / x-3-5 / 4x + 1 = 1
150 / 5 = 30 km
（30+6）/（1+3）
=36/4
=9 km
2x+3【2x-1】=16-【x+1】
2x+6x-3=16-x-1
8x=18
x=2.25
2 / x-3-5 / 4x + 1 = 1
x/2-4/5x=3
-0.3x=3
x=-10
Come on, a motorcycle and B bike from two places 250 kilometers apart at the same time. After five hours, they meet. What is the distance a travels per hour
It is known that the distance a travels per hour is three times that B travels per hour, less than six kilometers
Find the speed of B's bicycle
If B rides his bicycle for 20 minutes first, a sets off again and goes in opposite directions. A meets each other 5 hours after starting, and other conditions remain unchanged, the speed of B's bicycle can be calculated
Have you checked the calculation?
1. If B's speed is x km / h, a's speed is 3x-6 km / h, then 250 = 5 (x + 3x-6) 250 = 20x-30 x = 14, so B's speed is 14 km / h, a's speed is 14 * 3-6 = 36 km / h. 2. If B's speed is y km / h, 250 = 5 (y + 3y-6) + 1 / 3 * y 250 = 20y-30 + Y / 3
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