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Car a and car B leave from two places 650 meters apart at the same time. Car a travels 65 km per hour. After 6.5 hours, the two cars meet on the way. How many km per hour does car B travel
1. 5 + 6.5x = 650422.5 + 6.5x = 6506.5x = 650-422.56.5x = 227.5x = 227.5 / 6.5x = 35 A: B travels 35 kilometers per hour. 2. When the formula meets, a travels 65 * 6.5 = 422.5 kilometers, so B travels 650-422.5 = 227.5 kilometers
Two cars a and B drive from two places 225 kilometers apart at the same time. After 2.5 hours of meeting, car a travels 48 kilometers per hour, and how many kilometers per hour does car B travel?
225 △ 2.5-48 = 90-48 = 42 km. A: car B travels 42 km per hour
A and B leave each other from a and B. A is 48km / h, B is 54km / h. When the two cars meet, the distance between them is 36km. How many kilometers are there between a and B?
The distance between the two places is (48 + 54) × 12 = 102 × 12 = 1224 km. A: the distance between the two places is 1224 km
RT triangle angle c equals 90 degrees,. AC equals 9. BC equals 12?
It can be solved by equal area method
Suppose that the distance between point C and ab is x, there must be ac.bc1/2=ab X1 / 2, substituting the data, we can get x = 36 / 5
So the distance from point C to AB is 36 / 5
Please criticize and correct the shortcomings
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