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The two trains run opposite each other from AB, and the speed of the local train is 5 / 7 of that of the express train. After 4 hours, they meet 48 meters from the midpoint, so as to find the distance between the speed of the local train and ab `Urgent - urgent~`````
Let v be the speed of the fast train, then the slow train is 5 / 7V. Let t be the time of meeting, then the distance of the fast train VT is 5 / 7vt. Draw a graph, you can know that the fast train has walked 96 meters more than the slow train, then vt-5 / 7vt = 96. Bring in the data, and V = 84m / h (a little slow --, the topic should be 48km, I'll just take it as a meter, I'll see how to change it)
A and B are running from AB and meet at a distance of one fifth from the midpoint of ab. the speed ratio of fast and slow cars is (): ()
It's OK to write or not. Make sure it's right
A and B are running from AB and meet at a distance of one fifth from the midpoint of ab. the speed ratio of fast and slow cars is (): ()
Distance of slow car = 1 / 2 × (1-1 / 5) = 1 / 2 × 4 / 5 = 2 / 5
The distance of express train is 1-2 / 5 = 3 / 5
Then the speed ratio of express train to local train = distance ratio = 3 / 5:2 / 5 = 3:2
The speed of car a is 8 / 7 of that of car B. the two cars are facing each other at the same time from station a and station B, and they meet at 30 kilometers away from the midpoint. How many kilometers did car a travel when they meet?
Hello
Distance 30x2 ÷ (8-7) x (8 + 7) = 60x15 = 900km
A walked 900 △ (8 + 7) X7 = 420 km
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The speed of car a is 5 / 6 of that of car B. the two cars are facing each other from station a and station B at the same time. They meet at 2 km away from the midpoint. What is the distance between the two stations
Primary school can understand
The speed of car a is 5 / 6 of that of car B, which means that when they meet, the distance of car a is also 5 / 6 of that of car B
Now it's 2km away from the center, which means that car B is 2km away from the center, while car a is 2km away, so their distance difference is 2 + 2 = 4km
Now the distance of car B is 1, and that of car a is 5 / 6. The difference between them is 4 km. So the distance of car a is:
4 / (1-5 / 6) = 24 (km)
So the total distance is:
24 + 4 + 24 = 52 (km)
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