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The speed of a, B and C is 30 meters, 40 meters and 50 meters per minute respectively. A and B are in place a, while C is facing each other at the same time in place B. C meets a 10 minutes after meeting B. the road between a and B is () meters long A. 3600B. 4800C. 5600D. 7200
(30 + 50) × [(50 × 10 + 40 × 10) / (40-30)] = 80 × 90 = 7200 (m) answer: the distance between a and B is 7200 M
The speed of a, B and C is 30, 40 and 50 meters per minute respectively. A and B are in place a, C is in place B, and they are facing each other at the same time. C meets a 10 minutes after meeting B, so how about the distance between a and B?
Let the distance be s, and it takes x to meet B
s=40x+50x
s=(30+50)(x+10)
S = 7200
The speed of a, B and C is 30 meters, 40 meters and 50 meters per minute respectively. A and B are in place a, while C is facing each other at the same time in place B. C meets a 10 minutes after meeting B. the road between a and B is () meters long
A. 3600B. 4800C. 5600D. 7200
(30 + 50) × [(50 × 10 + 40 × 10) / (40-30)] = 80 × 90 = 7200 (m) answer: the distance between a and B is 7200 M
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