The speed ratio of car a and car B is 5:4. After the two cars meet, car B travels 18 kilometers more per hour than before,

The speed ratio of car a and car B is 5:4. After the two cars meet, car B travels 18 kilometers more per hour than before,

V b: v a = 4:5
4 (V B + 18) = 5 * V A
V b = 32km / h
*V A
=40KM\h

Party A and Party B travel from two places. It is known that the speed of Party A is 12km / h, and that of Party B is 14km / h. they meet at 5 o'clock to find the distance between the two places

（ 12 + 14）* 5 =130
The distance between the two places is 130 km

When a runs from point a to point B at 12km / h and B runs from point B to point a at 14km / h, B runs 1.5km more than a when two vehicles meet
When a runs from point a to point B at 12km / h and B runs from point B to point a at 14km / h, when the two vehicles meet, B runs 1.5km more than a, and what is the distance between a and B

B drives 14-12 more than a per hour = 2 (km)
1.5 △ 2 = 0.75 (hours), that is, it took 0.75 hours for two cars to meet
Distance = encounter time × speed and distance
(14 + 12) × 0.75 = 19.5 (km)

A and B depart from ab at the same time. The speed of B is 9 / 10 of that of A. the distance between the two vehicles is 5km. After meeting, the two vehicles depart from the original speed
Keep going. When car a arrives at ground B, how far is car B from ground a?

Analysis: when meeting, a walks one more share than B, 10km away
The total distance of the two cars is 19, that is, the whole journey = 10 × 19 = 190km
When a is finished, B is 9 / 10
Therefore, there is still 1 / 10, that is, 19 km
5 × 2 ÷ (1 / 19) × (1-9 / 10) = 19 km