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Car a and car B leave each other at the same time. Car a travels 42km per hour and car B travels 45km per hour. The two cars meet 18km from the midpoint. How many kilometers is the distance between a and B?
Let this process take t hours,
The results are as follows:
45t-(45t+42t)/2=18
T = 12
a. B distance between the two places: 45 * 12 + 42 * 12 = 1044 km
A: A and B are 1044 km apart
The two cars run from east to west at the same time. Car a runs 56 kilometers per hour and car B runs 48 kilometers per hour. The two cars meet at 32 km from the midpoint
How many kilometers is the distance between the East and the west?
The difference between each hour is 56-48 = 8km, and the first row is 64km more than the second row, so it is 64g8 = 8h, and the distance between the two places is (56 + 48) * 8 = 832km
The equation is like this
Suppose the distance is x kilometers
56【x/（56+48）】-x/2=32
At the same time, the passenger car and the freight car run in opposite directions from a and B. the passenger car runs 54km per hour, and the freight car runs 48km per hour. After the two cars meet, they continue to walk. When they arrive at the place of departure, they immediately return and meet at 108km from the midpoint to calculate the total length?
I don't know what grade you are in. Do you have any requirements to solve the problem? Suppose that the bus and the freight car are at the same speed, then the two cars will meet at the midpoint every time! That is to say, if the two cars are 108km away from the midpoint, the freight car should also be 108km away from the midpoint
A and B start from two places at the same time and meet each other after 4 hours. When they meet, car a travels 32 km more than car B. It is known that car B travels 50 km per hour on average,
How many kilometers does a car travel per hour on average
Set a car to run x kilometers per hour
x-32÷4=50
x-8=50
x=58
A: car a runs 28 kilometers per hour
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